Consider the following statements:
Statement 1: If $y={\log }_{10}x+{\log }_{e}x$, then $\frac{dy}{dx}=\frac{{\log }_{10}e}{x}+\frac{1}{x}$.
Statement 2: $\frac{d}{dx}\left({\log }_{10}x\right)=\frac{\log x}{\log 10}$ and $\frac{d}{dx}\left({\log }_{\mathit{e}}x\right)=\frac{\log x}{\log e}$.