Convert $\frac{5}{37}$ as a recurring decimal.

What will be the minimum value of $x$ so that  $\frac{55}{x-19}$ becomes a complete number?

Convert 18 into binary number?

Simplify : $\frac{9+2\times 3.3}{0.003}$

(A) 12,100 

(B) 5,200 

(C) 520 

(D) 1,210 

What is the fraction which is subtracted from$\frac{1}{2}$, the leaves $\frac{3}{4}$?

Simplify: 25.67 + 9.208 + 152.1 + 63.2 

(A) 248.718 

(B) 250.718 

(C) 248.178 

(D) 250.178 

Simplify: $\left(\frac{1}{9}+\frac{3}{5}\right)$$÷$$\left(\frac{2}{9}+\frac{2}{5}\right)$

(A)$\frac{31}{27}$

(B)$\frac{33}{28}$

(C)$\frac{7}{8}$

(D)$\frac{8}{7}$

Which of the following fractions is the highest of all?

1. $\frac{5}{4}$

2. $\frac{4}{3}$

3. $\frac{3}{2}$

4. $\frac{6}{5}$

Which of the following alternatives is correct for the given number series?

(A)$\frac{2}{7}<\frac{21}{39}<\frac{12}{17}<\frac{29}{47}$

(B)$\frac{21}{39}<\frac{29}{47}<\frac{2}{7}<\frac{12}{17}$

(C)$\frac{2}{7}<\frac{21}{39}<\frac{29}{47}<\frac{12}{17}$

(D)$\frac{21}{39}<\frac{12}{17}<\frac{2}{7}<\frac{29}{47}$

A cake is distributed among 5 friends. Four of them get $\frac{1}{8}, \frac{1}{6}, \frac{5}{12}$ and $\frac{1}{12}$, and as shares. What part of the cake will be got by the fifth friend?

Simplify :

$1.123 + 11.23 + 112.3 = ?$

1. $123.453$
2. $132.143$
3. $124.653$
4. $134.643$