Current flows through uniform, square frames as shown. In which case is the magnetic field at the centre of the frame not zero?

A conductor $PQ$ carries a current '$i$' is placed perpendicular to a long conductor $XY$ carrying a current $I$. The direction of force on $PQ$ will be

A circular current loop of radius a is placed in radial field $B$ as shown. The net force acting on the loop is

A write $PQRST$ carrying current $I=5 \mathrm{A}$ is placed in uniform magnetic field $B=2 \mathrm{T}$ as shown in fig. If the length of part $QR=4 \mathrm{cm}$ and $SR=6 \mathrm{cm}$ then the magnetic force on $SR$ edge of the wire is

A conducting rod of length $L$ and mass $m$ is moving down a smooth inclined plane of inclination $\theta$ with constant velocity $v$ in fig. A current $I$ is flowing in the conductor in a direction perpendicular to paper inwards. A vertically upward magnetic field $\overrightarrow{B}$ exists in space. Then magnitude of magnetic field $\overrightarrow{B}$ is

A rectangular loop carrying a current $i$ is situated near a long straight wire such that the wire is parallel to one of the sides of the loop and is in the plane of the loop. If steady current $I$ is established in the wire as shown in the figure, the loop will :

Figure shows a square current carrying loop $ABCD$ of side $10 \mathrm{cm}$ and current $i=10 \mathrm{A}.$ The magnetic moment $\overrightarrow{M}$ of the loop is

Consider a triangular loop of wire with sides $a$ and $b$. The loop carries a current $I$ in the direction shown, and is placed in a uniform magnetic field that has magnitude $B$ and point in the same direction as the current in side $OM$ of the loop.

At the moment shown in the figure the torque on the current loop