Charles' law states that the volume of an ideal gas is directly proportional to the absolute temperature at constant pressure. This law was formulated in the year 1780 by French physicist Jacques Charles. It can be represented in the following manner. V ∝ T V T = K Hence, Charles' law equation is at two different volume and temperature can be expressed as: V 1 T 1 = V 2 T 2

Match the following: Column I (Temperature in Celsius) Column II (Temperature in Kelvin) (i) 0 C ∘ (a) 546 K (ii) 273 C ∘ (b) 293 K (iii) - 273 C ∘ (c) 290 K (iv) 20 C ∘ (d) 0 K (v) 17 C ∘ (e) 273 K

The Kelvin, unit of thermodynamic temperature, is the fraction 1 273 . 16 of the thermodynamic temperature of the triple point of water. The unit of Celsius temperature is the degree Celsius, symbol C ∘ , which is by definition equal in magnitude to the Kelvin. The relationship between Celsius and Kelvin is as follows, K = ° C + 273 Therefore, K = 0 + 273 K = 273 Temperature is measured in Celsius ° C , Fahrenheit ° F and Kelvin K . Kelvin is the SI unit of temperature. The relationship between Celsius and Kelvin is as follows, K = ° C + 273 K = 273 + 273 K = 546 The absolute zero is the lowest limit of temperature at which the volume becomes theoretically zero. The temperature for absolute zero is - 273 ° C . K = ° C + 273 K = - 273 + 273 K = 0 20 ° C is equal to 293 K , as the K = ° C + 273 . The standard temperature is 0 ° C or 273 K . According to relation between Celsius and Kelvin, K = ° C + 273 . Therefore 17 ° C is equal to 290 K . Column I (Temperature in Celsius) Column II (Temperature in Kelvin) 0 C ∘ 273 K 273 C ∘ 546 K - 273 C ∘ 0 K 20 C ∘ 293 K 17 C ∘ 290 K

Convert 15 C ∘ temperature into Kelvin.

Temperature is measured in Celsius ° C , Fahrenheit ° F and Kelvin K . Kelvin is the SI unit of temperature. The relationship between Celsius and Kelvin is as follows, K = ° C + 273 . 15 K = 15 + 273 . 15 K = 288 . 15 K

E M B I B E

TOGETHER WITH CHEMISTRY>Chapter 7 - Study of Gas Laws>Self Evaluation Test>Q 1

EASY

9th ICSE

IMPORTANT

Earn 100

Define Charles' law.

Important Questions on Study of Gas Laws

MEDIUM

9th ICSE

IMPORTANT

TOGETHER WITH CHEMISTRY>Chapter 7 - Study of Gas Laws>Self Evaluation Test>Q 2

Name the quantity which is constant in

(i) Boyle's law

(ii) Charles' law

MEDIUM

9th ICSE

IMPORTANT

TOGETHER WITH CHEMISTRY>Chapter 7 - Study of Gas Laws>Self Evaluation Test>Q 3

What will be the pressure required to reduce

600 mL

of a dry gas at

750 mm

pressure to

500 mL

at the same temperature.

MEDIUM

9th ICSE

IMPORTANT

TOGETHER WITH CHEMISTRY>Chapter 7 - Study of Gas Laws>Self Evaluation Test>Q 4

Match the following:

Column I (Temperature in Celsius)	Column II (Temperature in Kelvin)
(i) $0 {}^{\circ}C$	(a) $546 K$
(ii) $273 {}^{\circ}C$	(b) $293 K$
(iii) $- 273 {}^{\circ}C$	(c) $290 K$
(iv) $20 {}^{\circ}C$	(d) $0 K$
(v) $17 {}^{\circ}C$	(e) $273 K$