Solubility product of Ag 2 CrO 4 is 1 × 10 - 12 . What is the solubility of Ag 2 CrO 4 in 0 . 01 M AgNO 3 solution?

Given that K sp = 1 × 10 - 12 The dissociation of Ag 2 CrO 4 is given as: Ag 2 CrO 4 ( s ) ⇌ 2 Ag + ( aq ) + CrO 4 - 2 ( aq ) 2 s s AgNO 3 ( s ) ⇌ Ag + ( aq ) + NO 3 - ( aq ) 0 . 01 M 0 . 01 K sp = [ Ag + ] 2 [ CrO 4 2 - ] 1 × 10 - 12 = ( 2 s + 0 . 01 ) 2 ( s ) [ Ag + ] = 2 S + 0 . 01 ; 0 . 01 > > 2 s ; so , [ Ag + ] = 0 . 01 ; [ CrO 4 2 - ] = s s = 1 × 10 - 12 ( 10 - 2 ) 2 = 1 × 10 - 8 M

A saturated solution, prepared by dissolving CaF 2 ( s ) in water, has [ Ca 2 + ] = 3 . 3 × 10 - 4 M . What is the K sp of CaF 2 ?

The dissociation of CaF 2 is: CaF 2 ( s ) ⇌ Ca 2 + ( aq ) + 2 F - ( aq ) [ F - ] = 2 [ Ca 2 + ] = 2 × 3 . 3 × 10 - 4 M = 6 . 6 × 10 - 4 M K sp = [ Ca 2 + ] [ F - ] 2 = ( 3 . 3 × 10 - 4 ) ( 6 . 6 × 10 - 4 ) 2 = 1 . 44 × 10 - 10

K sp of AgCl is 1 . 8 × 10 - 10 . Calculate molar solubility in 1 M AgNO 3 .

Here 'x' is solubility: AgCl ( s ) ⇌ Ag x + ( aq ) + Cl x - ( aq ) AgNO 3 ( aq ) ⇌ Ag + ( aq ) + NO 3 - ( aq ) 1 M 1 M [ Ag + ] = x + 1 ( x < < 1 ) ⇒ 1 [ Cl - ] = x K sp = [ Ag + ] [ Cl - ] 1 . 8 × 10 - 10 = ( 1 ) ( x ) x = 1 . 8 × 10 - 10 M

A particular saturated solution of silver chromate Ag 2 CrO 4 has [ Ag + ] = 5 × 10 - 5 and [ CrO 4 ] 2 - = 4 . 4 × 10 - 4 M . What is the value of K sp for Ag 2 CrO 4 ?

The dissociation of Ag 2 CrO 4 is Ag 2 CrO 4 ( s ) ⇌ 2 Ag + ( aq ) + CrO 4 2 - ( aq ) K sp = [ Ag + ] [ CrO 4 2 - ] = ( 5 × 10 - 5 ) 2 × ( 4 . 4 × 10 - 4 ) = 1 . 1 × 10 - 12

K sp of Ag 2 CrO 4 is 1 . 1 × 10 - 12 . What is solubility of Ag 2 CrO 4 in 0 . 1 M K 2 CrO 4 ?

Here ' x ' is the solubility: Ag 2 CrO 4 ⇌ 2 Ag + + CrO 4 2 - 2 x x K 2 CrO 4 ⇌ 2 K + + CrO 4 2 - 0 . 2 M 0 . 1 M [ Ag + ] = 2 x [ CrO 4 2 - ] = ( x + 0 . 1 ) ≈ 0 . 1 ( x < < 0 . 1 ) K sp = [ Ag + ] 2 [ CrO 4 2 - ] 1 . 1 x 10 - 12 = ( 2 x ) 2 ( 0 . 1 ) 1 . 1 x 10 - 12 = 0 . 4 x 2 x 2 = 1 . 1 × 10 - 12 0 . 4 x = 1 . 1 × 10 - 12 0 . 4 x = 1 . 65 × 10 - 6 M