The mass of the planet Jupiter is 1 .9 × 10 27 kg and that of the sun is 1 .99 × 10 30 kg . The mean distance of Jupiter from the sun is 7 .8 × 10 11 m . Calculate the gravitational force which the sun exerts on Jupiter.

Given, Mass of the Jupiter, M = 1 . 99 × 10 30 kg Mass of the sun, m = 1 . 9 × 10 27 kg Distance between Jupiter and sun, d = 7 . 8 × 10 11 m The value of universal gravitational constant, G = 6 . 67 × 10 - 11 N m 2 kg 2 The equation for gravitational force is, F = G M m d 2 Substituting the values, ⇒ F = 6 .67 × 10 − 11 × 1 .99 × 10 30 × 1 .9 × 10 27 ( 7 .8 × 10 11 ) 2 ⇒ F = 4 .15 × 10 23 N Hence, the sun exerts 4 .15 × 10 23 N gravitational force on Jupiter.

E M B I B E

LIVING SCIENCE PHYSICS 9>Chapter 3 - Gravitation>Check Your Progress>Q 2

MEDIUM

9th CBSE

IMPORTANT

Earn 100

Derive the formula for the calculation of gravitational force exerted by a body of mass $m_{1}$ on another body of mass $m_{2}$ separated by a distance $d$ .

Important Questions on Gravitation

EASY

9th CBSE

IMPORTANT

LIVING SCIENCE PHYSICS 9>Chapter 3 - Gravitation>Check Your Progress>Q 3

Newton's Law of gravitation is also called inverse square law. Give reasons.

EASY

9th CBSE

IMPORTANT

LIVING SCIENCE PHYSICS 9>Chapter 3 - Gravitation>Check Your Progress>Q 4

Why is Newton's law of gravitation also known as Universal Law?

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9th CBSE

IMPORTANT

LIVING SCIENCE PHYSICS 9>Chapter 3 - Gravitation>Check Your Progress>Q 5

If the distance between two objects is increased four times, then by how many times should the mass of one of the objects be changed to maintain the same gravitational force?

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9th CBSE

IMPORTANT

LIVING SCIENCE PHYSICS 9>Chapter 3 - Gravitation>Check Your Progress>Q 6

Calculate the force of gravitation between two objects of masses of