MEDIUM
Earn 100

Derive the formula for the molar specific heat capacity at constant volume of a mixture of two gases.

Important Questions on Molecular Properties of Matter

MEDIUM

Two different metal bodies A and B of equal mass are heated at a uniform rate under similar conditions. The variation of temperature of the bodies is graphically represented as shown in the figure. The ratio of specific heat capacities is:

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EASY
The values of Cp and Cv for a diatomic gas are respectively (R=g a s constant)
MEDIUM
The correct relation between the degrees of freedom f and the ratio of specific heat γ is:
MEDIUM

Match the following: (where R is gas constant)

  Column I   Column II
(a) Molar specific heat of helium gas at constant volume (i) 3 R
(b) Molar specific heat of oxygen at constant volume (ii) 3.5 R
(c) Molar specific heat of carbon dioxide at constant volume (iii) 1.5 R
(d) Molar specific heat of hydrogen at constant pressure (iv) 2.5 R
HARD
The specific heats, Cp and Cv of a gas of diatomic molecules, A, are given (in units of J mol-1 K-1 ) by 29 and 22, respectively. Another gas of diatomic molecules, B, has the corresponding values 30 and 21. If they are treated as ideal gases, then:
HARD

For a monoatomic ideal gas following the cyclic process ABCA shown in the U vs ρ plot, identify the incorrect option:

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MEDIUM
One mole of a monoatomic ideal gas undergoes a quasistatic process, which is depicted by a straight line joining points V0,T0 and 2V0,3T0 in a V-T diagram. What is the value of the heat capacity of the gas at the point V0,T0?
MEDIUM
The ratio of specific heats CPCV in terms of degree of freedom f is given by :
HARD
Consider a mixture of n moles of helium gas and 2n moles of oxygen gas (molecules taken to be rigid) as an ideal gas. Its CPCV value will be:
MEDIUM
Two moles of an ideal gas, with CPCV=53, are mixed with three moles of another ideal gas CPCV=43. The value of CPCV for the mixture is
HARD

1 mole of gas with γ=75 is mixed with 1 mole of gas with γ=53, then the value of γ for the resulting mixture is

EASY
For a rigid diatomic molecule, the universal gas constant R=nCP, where, CP is the molar specific heat at constant pressure and n is a number. Hence, n is equal to
EASY
For a gas if γ=1.4, then atomicity, specific heat capacity at constant pressure and specific heat capacity at constant volume of the gas are respectively
EASY
For a gas CP-CV=R in a state P and CP-CV=1.10R in a state Q,TP and TQ are the temperatures in two different states P and Q, respectively. Then
EASY

A monoatomic gas performs a work of Q4, where Q is the heat supplied to it. The molar heat capacity of the gas will be _____ R during this transformation, where R is the gas constant.

EASY
The molar specific heat of an ideal gas at constant pressure and constant volume is Cp and Cυ respectively. If R is the universal gas constant and the ratio of Cp to Cυ is γ then Cυ=
EASY
Let γ1 be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ2 be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio γ1γ2 is:
MEDIUM
Consider two ideal diatomic gases A and B at some temperature T . Molecules of the gas A are rigid, and have a mass m . Molecules of the gas B have an additional vibrational mode and have a mass m4 . The ratio of the specific heats CV Aand  CVB of gas A and B, respectively is:
EASY
An ideal gas has molecules with 5 degrees of freedom. The ratio of specific heats at constant pressure Cp and at constant volume CV is:
EASY
Cp-Cv=RM and Cv are specific heats at constant pressure and constant volume respectively. It is observed that, Cp-Cv=a for hydrogen gas and Cp-Cv=b for nitrogen gas. The correct relation between a and b is: