Describe J. J. Thomson's atomic model. 

Identify the sets of quantum numbers which are not possible?

$$\begin{gathered} \mathrm{a}. \mathrm{n}=0, \mathrm{l}=0, {\mathrm{m}}_1= 0, {\mathrm{m}}_{\mathrm{s}}= +\frac{1}{2} \\ \mathrm{b}. \mathrm{n}=1, \mathrm{l}=0, {\mathrm{m}}_1= 0, {\mathrm{m}}_{\mathrm{s}}= -\frac{1}{2} \\ \mathrm{c}. \mathrm{n}=1, \mathrm{l}=1, {\mathrm{m}}_1= 0, {\mathrm{m}}_{\mathrm{s}}= +\frac{1}{2} \\ \mathrm{d}. \mathrm{n}=2, \mathrm{l}=1, {\mathrm{m}}_1=0, {\mathrm{m}}_{\mathrm{s}}=-\frac{1}{2} \end{gathered}$$

In Thomson's experiment for the determination of $\left(\frac{\mathrm{e}}{\mathrm{m}}\right)$ of electron, electric field of intensity $\text{'}\mathrm{E}\text{'}$ only is applied. Now the deflection produced by the electron beam is directly proportional to:

Match List$‐\mathrm{I}$ (Experiment performed) with List$‐\mathrm{II}$ (Phenomena discovered/associated)and select the correct option from the options given below the lists

Match the following :
List -I :
(a) Frequency of distribution of the emitted radiation from a black body
(b) Spin quantum numbers(m_s)
(c) Angular Momentum
(d) All orbital have equal energy

List - II :
(i) degeneracy
(ii) temperature dependent
(iii) vector quantity
(iv) mass times velocity times radius 

Codes:

Nitrogen (atomic number $7$) and phosphorus (atomic number $15$) belong to group $15$  of the Periodic Table. Write the electronic configuration of these two elements. Which one of these will be more electronegative? Why? 

Consider the following statement:

(I) All isotopes of elements have the same number of neutrons.

(II) Only one isotope of an element can be stable and non-radioactive.

(III) All elements have isotopes.

(IV) All isotopes of Carbon can form chemical compounds with Oxygen$-16$.

The correct option regarding an isotope is: