The histogram shows the lengths of 26 black rats. Write down the modal class.

The histogram shows the lengths of 26 black rats. The modal class is the class interval that is lengths interval with the highest frequency. So, here we have highest frequency of 9 in class 36 - 40 So, 36 - 40 is the modal class of given data

The histogram shows the lengths of 26 black rats. Find the class interval that contains the median.

The histogram shows the lengths of 26 black rats. The table of given data Length ( cm ) Frequency cumulative frequency 28 - 32 4 4 32 - 36 4 8 36 - 40 9 17 40 - 44 9 26 44 - 48 6 32 48 - 52 3 35 Now, let n = sum of all frequencies n = 4 + 4 + 9 + 9 + 6 + 3 = 35 as n is odd, so the position of median is the n + 1 2 th term Therefore, the position of median is = 35 + 1 2 = 18 th term of frequency So, the frequency of 18 will be possible in 40 - 44 interval. So, the median will be in the interval 40 - 44 .

The histogram shows the lengths of 26 black rats. Calculate an estimate for the range.

The histogram shows the lengths of 26 black rats. The table of given data Length ( cm ) Frequency 28 - 32 4 32 - 36 4 36 - 40 9 40 - 44 9 44 - 48 6 48 - 52 3 Now, the range of given data is the difference between the highest and lowest value of length. So, Range = 52 - 28 = 24 Therefore, the estimated range is 24 cm .

The histogram shows the lengths of 26 black rats. Describe the distribution.

An outlier is a data point that is far away from the rest of the dataset. Outliers do not have a formal definition, but are easy to determine by looking at histogram. here, we have no outliers. Modal class of given data is 36 - 40 as it has highest frequency. Modality describes the number of peaks in a dataset. A unimodal distribution in a histogram means there is one distinct peak indicating the most frequent value in a histogram. So, this is a unimodal distribution as we have only one peak. The distribution of the data is symmetric if it has one prominent peak and equal tails to the left and the right. So, the distribution is Relatively symmetrical. Therefore, the distribution is Relatively symmetrical, unimodal and has no outliers.

The histogram shows the amounts of money, to the nearest $ 10 , some families spend on food each week. Calculate an estimate for the mean amount spent on food.

Given histogram shows the Amount spent on food by some families Amount spent on food is plotted on x -axis and frequency is plotted on y -axis. For finding estimated mean amount for this grouped data we make a column of midpoint of each class interval. So, the grouped frequency table is Amount spent on food Mid point of interval x Frequency f 145 7 155 17 165 12 175 4 Now, the mean amount spent on food is = ∑ f x ∑ f = 145 × 7 + 155 × 17 + 165 × 12 + 175 × 4 7 + 17 + 12 + 4 = 6330 40 = 158 . 25 So, the estimated mean amount spent on food is 158 . 25 dollars.