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Dimensional formula for coefficient of restitution

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Important Questions on Laws of Motion

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A body having mass m and moving with velocity 3 km h-1 collides with a body at rest having mass  2 m and sticks to it. The combined mass will begin to move with a velocity,
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A particle falls from a height h on a fixed horizontal surface and rebounds. If e is the coefficient of restitution, then the total distance travelled by the particle before it stops rebounding is,
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A ball moving with a momentum 5 kg m s-1 strikes a wall. If the initial and final momenta make equal angles of 45°, then magnitude in change in momentum is,
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A bullet of mass 4.2×10-2 kg moving at speed of 300 m s-1 gets stuck into a block with a mass 9 times that of the bullet. If the block is free to move without any kind of friction, the heat generated in the process will be,
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A particle of mass m moving in the x-direction with speed 2v is hit by another particle of mass 2m moving in the y-direction with speed v. If the collision is perfectly inelastic, the percentage loss in the energy during the collision is close to,
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A bag of mass M hangs by a long thread and a bullet (mass m) comes horizontally with velocity v and gets caught in the bag. Then for the combined (bag + bullet) system
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A block of mass 2 kg collides with identical stationary block head on elastically with velocity of 20 m s-1. After collision second block collides with the third block of mass 2 kg initially at rest. If they collide head on perfectly inelastically then the velocity of their combination will be

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In elastic collision, 100 % energy transfer takes place when