Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is :

${\mathrm{NaClO}}_3$ is used, even in spacecrafts, to produce ${\mathrm{O}}_2.$ The daily consumption of pure ${\mathrm{O}}_2$ by a person in $492 \mathrm{L}$ at $1$ atm, $300\mathrm{K}.$ How much amount of ${\mathrm{NaClO}}_3,$ in grams, is required to produce ${\mathrm{O}}_2$ for the daily consumption of a person at $1$ atm, $\mathrm{}300\mathrm{K}$ ? 

${\mathrm{NaClO}}_3\left(\mathrm{s}\right)+\mathrm{Fe}\left(\mathrm{s}\right)\to {\mathrm{O}}_2\left(\mathrm{g}\right)+\mathrm{NaCl}\left(\mathrm{s}\right)+\mathrm{FeO}\left(\mathrm{s}\right)$
$\mathrm{R}=0.082 \mathrm{L} \mathrm{atm} {\mathrm{mol}}^{-1} {\mathrm{K}}^{-1}$

Give answer to the nearest integer value.