A man travelled 3 4 of his journey by bus, 1 5 by taxi and remaining 5 km on foot. Find the total distance of his journey.

From the given, Let the total journey be x km , then according to the question ; A man travelled by bus = 3 4 of x A man travelled by taxi = 1 5 of x Remaining a man travelled by foot = 5 km Remaining distance = x - 3 4 x + 1 5 x 5 = x - 3 4 x + 1 5 x 5 = x - 3 x 4 + x 5 5 = x - 15 x 20 + 4 x 20 5 = x - 19 x 20 5 = 20 x 20 - 19 x 20 5 = x 20 x = 5 × 20 = 100 Hence, the distance of the total journey is 100 km .

Solve the following linear equation. 5 x - 4 8 - x - 2 5 = x + 6 4

From the given, 5 x - 4 8 - x - 2 5 = x + 6 4 5 x - 4 8 - x - 2 5 - x + 6 4 = 0 ( Transposing x + 4 2 on L.H.S ) L.C.M of 8 , 5 and 4 is 40 . ⟹ 5 5 x - 4 - 8 x - 3 - 10 x + 4 40 = 0 ⟹ 5 × 5 x - 5 × 4 - 8 × x + - 8 × - 3 - 10 × x + - 10 × 4 40 = 0 ⟹ 25 x - 20 - 8 x + 24 - 10 x - 40 40 = 0 ⟹ 25 x - 8 x - 10 x - 20 + 24 - 40 40 = 0 ⟹ 7 x - 36 40 = 0 ⟹ 7 x - 36 40 × 40 = 0 × 40 ( Multiplying both sides 40 ) ⟹ 7 x - 36 = 0 ⟹ 7 x = 36 ( Transposing - 36 on R.H.S ) ⟹ x = 36 7 ( Transposing 7 on R.H.S) Hence, the required answer is as shown above.

E M B I B E

I Did It>Chapter 6 - Linear Equations in One Variable>Exercise 6.2>Q 18

MEDIUM

7th CBSE

IMPORTANT

Earn 100

Divide $96$ into two parts such that half of one part is equal to the other part.

Important Questions on Linear Equations in One Variable

HARD

7th CBSE

IMPORTANT

I Did It>Chapter 6 - Linear Equations in One Variable>Exercise 6.2>Q 19

A box contains $₹ 1$ coins and $₹ 2$ coins whose total value is $₹ 70$ . If the number of $₹ 1$ coins is five times that of $₹ 2$ coins, find the number of coins of each type.