In a meter bridge, the balance point is found to be at 39 . 5 cm from A . When the resistor Y is of 12 . 5 Ω . Determine balance point of the bridge above, if X and Y are interchanged.

If X and Y are inter charged, then l 1 and 100 - l , get inter charged . The balance point of the bridge will be 100 - l 1 from A. 100 - l 1 = 100 - 39 . 5 = 60 . 5 c m . Therefore, the balance point is 60 . 5 c m from A .

In a meter bridge, the balance point is found to be at 39 . 5 cm from A . When the resistor Y is of 12 . 5 Ω . What happens if the galvanometer and cell are interchanged at the balance point of the bridge?

When the galvanometer and cell are interchanged at the balance point of the bridge, the galvanometer will show no deflection. Hence, no current would flow through the galvanometer.

Three resistors 1 Ω , 2 Ω , 3 Ω are combined in series. ii If the combination is connected to a battery of emf 12 V , and negligible internal resistance, obtain the potential drop across the resistor.

Current in the circuit is given by I = E R I = 12 6 = 2 Ω Potential drop across 1 Ω , V 1 = I R 1 = 2 × 1 = 2 V Potential drop across 2 Ω , V 2 = I R 2 = 2 × 2 = 4 V Potential drop across 3 Ω , V 3 = I R 3 = 2 × 3 = 6 V ...

Three resistors 1 Ω , 2 Ω , 3 Ω are combined in series. i What is the total resistance of the combination?

Equivalent resistance is R e q = R 1 + R 2 + R 3 = 1 + 2 + 3 Ω = 6 Ω . The total resistance of the combination is - F = q E + q v × B . ∮ H . d L = I e n c .

In a meter bridge, the balance point is found to be at 39 . 5 cm from A . When the resistor Y is of 12 . 5 Ω . What happens if the galvanometer and cell are interchanged at the balance point of the bridge?

When the galvanometer and cell are interchanged at the balance point of the bridge, the galvanometer will show no deflection. Hence, no current would flow through the galvanometer.

In a meter bridge, the balance point is found to be at 39 . 5 cm from A . When the resistor Y is of 12 . 5 Ω . Determine balance point of the bridge above, if X and Y are interchanged.

If X and Y are inter charged, then l 1 and 100 - l , get inter charged . The balance point of the bridge will be 100 - l 1 from A. 100 - l 1 = 100 - 39 . 5 = 60 . 5 c m . Therefore, the balance point is 60 . 5 c m from A .