
Draw a regular pentagon and then a triangle of the same area.
Important Questions on Constructions

Arrange the following steps of construction of in which and in correct sequence.
Step I : Join.
Step II : From ray , cut off line segment
Step III : Draw a line segment of length .
Step IV : Draw a perpendicular bisector of meeting at point . Join to obtain .
Step V: Draw at point of line segment .



Arrange the following steps of construction of a in which and the difference between the other two sides is in correct sequence.
Step I : Set off .
Step II : Draw .
Step III: Construct
Step IV: Join . Then, is the required triangle.
Step V: Draw the right bisector of , meeting produced at .
Step VI: Join .

Steps of construction of triangle in which and are given below.
Draw .
Construct
Cut off on . Join .
Draw perpendicular bisector for , meeting produced at .
Join . Then is the required triangle.
Which of the above step(s) is/are incorrect?

Can you construct , in which , and perimeter of is ?


Arrange the following steps of construction of a in which and in correct sequence.
Step I : Make an angle at point of base .
Step II : Join and draw the perpendicular bisector of that intersect at .
Step III : Draw the base of length .
Step IV : Join to obtain .
Step V: Cut the line segment from the ray .


Study the statements carefully and select the correct option.
Statement-I : The sum of any two sides of a triangle is always greater than the third side.
Statement-II : It is possible to construct a in which and .

Arrange the following steps of construction of a , in which and in correct sequence.
Step : Draw the perpendicular bisector of meeting at .
Step : Draw .
Step : Join .
Step : From ray , cut off line segment equal to i.e, .
Step : Draw
Step : Join to obtain the required .


A triangle, , with and can be constructed.


Which of the following steps of construction is incorrect while constructing a of perimeter and .
Step I : Draw a line segment equal to the perimeter of .
Step II : Construct and .
Step III : Draw bisectors of angles and and mark their intersection point as .
Step IV : Draw the perpendicular bisectors of and meeting in and respectively.
Step V: Join and to obtain the required triangle .




Study the statements carefully and select the correct option.
Statement-I: It is possible to construct a triangle whose sides measure and .
Statement-II : It is possible to construct an angle of using ruler and compass only.

