Draw a vertical line $l$ and a line parallel to it at a distance of $3 \mathrm{cm}$.

The steps to construct a $∆\mathrm{P}\mathrm{Q}\mathrm{R}$ with $\mathrm{Q}\mathrm{R}=4 \mathrm{c}\mathrm{m}, \mathrm{P}\mathrm{Q}=5 \mathrm{c}\mathrm{m} \mathrm{a}\mathrm{n}\mathrm{d} \mathrm{Q}\mathrm{R}=5.5 \mathrm{c}\mathrm{m}$ are given below in a jumbled order. Arrange the steps in the correct order.

(a) With $\mathrm{Q}$ as centre and a radius equals to $5 \mathrm{cm}$, draw an arc.

(b) Draw a line segment $\mathrm{QR}$ of $4 \mathrm{cm}$.

(c) Join $\mathrm{P}$ and $\mathrm{Q}$, and $\mathrm{P}$ and $\mathrm{R}$. $△\mathrm{PQR}$ is the required triangle.

(d) With $\mathrm{R}$ as the centre and a radius of $5.5 \mathrm{cm}$, draw another arc intersecting the previous arc at $\mathrm{P}$.