Name: The Altitude of a Triangle
Uploaded: 2019-07-19
Duration: 2 min 45 s
Description: The orthocentre is made by intersecting the altitudes drawn from all the vertices to the triangle's opposite sides. But what is altitude? Watch this video to...

Question

Draw an acute angled

△ P Q R

. Draw all of its altitudes. Name the point of concurrence as

' O'

.

Accepted Answer

In acute angled triangle, all interior angles are less than $90 °$ .

Step $1 :$ Draw line segment $Q R$ of any length.

Step $2 :$ At $Q$ , draw an acute angle ( greater than $0 °$ but less than $90 °$ ) with the help of protractor.

Step $3 :$ Draw the line from $Q$ with given angle.

Step $4 :$ At $R$ , draw another acute angle with the help of protractor.

Step $5 :$ Draw line from $R$ with given angle.

Step $6 :$ Exceed line drawn from $Q$ and $R$ and mark the point of intersection as $P$ .

$△ P Q R$ is formed.

Step $7 :$ With $P$ as a centre and any convenient radius draw arcs to cut $Q R$ at two points $M, N$ and from that two points draw two arcs to intersect each other at a point $T$ . Join $T$ $P$ . In this way altitude from $P$ , i.e., $P A$ is drawn.

Step $8 :$ Similarly, from all three vertices, i.e., $P, Q, R$ draw perpendiculars on the opposite sides one by one, i.e., $P A, Q B, R C$ and name intersection of all three altitudes as $O$ . $O$ is known as the Orthocentre.

Draw an acute angled $△ P Q R$ . Draw all of its altitudes. Name the point of concurrence as $' O'$ .

Important Questions on Altitudes and Medians of a Triangle

Learn and Prepare for any exam you want !

Draw an acute angled △PQR. Draw all of its altitudes. Name the point of concurrence as 'O'.

Important Questions on Altitudes and Medians of a Triangle

Learn and Prepare for any exam you want !

Draw an acute angled $△ P Q R$ . Draw all of its altitudes. Name the point of concurrence as $' O'$ .