Draw orbital diagram of Ca 2 + 20 40 ion and state the number of three fundamental particles present in it.

Orbital diagram of Ca 2 + 20 40 ion is as follows: In Ca 2 + 20 40 where + 2 indicate that calcium lost its two valence electrons. So, its fundamental particles are: Number of electrons = 18 Number of protons = 20 Number of neutrons = 20

Draw orbital diagram of Ca 2 + 20 40 ion and state the number of three fundamental particles present in it.

Orbital diagram of Ca 2 + 20 40 ion is as follows: In Ca 2 + 20 40 where + 2 indicate that calcium lost its two valence electrons. So, its fundamental particles are: Number of electrons = 18 Number of protons = 20 Number of neutrons = 20

Write down the electronic configuration of the following: X 27 13 Write down the number of electrons in X .

X 27 13 Given symbol shows that: Atomic number Z = 13 . Electronic configuration = 2 , 8 , 3 So, number of electrons = 13 , The atomic number = 13 is of aluminium, it is a lightweight silvery white metal of main group 13 .

Write down the electronic configuration of the following: Y 35 17 Write down the number of neutrons in Y .

Y 35 17 Given symbol represent that: Atomic number = 17 . Electronic configuration 2 , 8 , 7 Hence, number of neutrons 35 - 17 = 18 . From the electronic configuration we can conclude that the given element is chlorine, as atomic number of chlorine is 17 . Chlorine Cl exists as a yellow green gas with a pungent smell. It has the atomic number 17 in the periodic table and belongs to Group 17 , the halogens. It is a non-metal with the symbol Cl .