
Each question consists of two statements, namely, Assertion and Reason . For selecting the correct answer, use the following code:
Assertion (A)
Reason (R)
If the median and mode of a frequency distribution are and respectively, then its mean is .
Mean, median and mode of a frequency distribution are selected as:
mode median mean.
Mean, median and mode of a frequency distribution are selected as:
mode median mean.


Important Questions on Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive
Assertion (A) | Reason (R) | ||||||||||||||
Consider the following frequency distribution:
The mode of the above data is |
The value of the variable which occurs most often is the mode. |



Consider the following distribution:
Class | |||||
Frequency |
The sum of the lower limits of the median class and the modal class is

Consider the following frequency distribution:
Class | |||||
Frequency |
The upper limit of the median class is


In the table given below, the times taken by athletes to run a -hurdle race are given.
Class | ||||||
Frequency |
Find the number of athletes who completed the race in less than seconds.

The annual profits earned by shops of a shopping complex in a locality are recorded in the table shown below:
Profit (in Lakhs Rs.) | Number of Shops |
More than or equal to | |
More than or equal to | |
More than or equal to | |
More than or equal to | |
More than or equal to | |
More than or equal to | |
More than or equal to |
If we draw the frequency distribution table for the above data, find the frequency corresponding to the class
