Electric field at a distance $x$ from the origin is given as $E=\frac{100 \mathrm{N}-{\mathrm{m}}^2 {\mathrm{C}}^{-1}}{x^2}.$ Then potential difference between the points situated at $x=10 \mathrm{m}$ and $x=20 \mathrm{m}$ is :-

The figure gives the electric potential $V$ as a function of distance through four regions on $x$-axis. Which of the following is true for the magnitude of the electric field $E$ in these regions?

As shown in the figure below, a point charge $q$ moves from point $P$ to a point $S$ traversing a path $PQRS$ in a uniform $\overrightarrow{E}.$ The electric field is directed along a direction parallel to $x$-axis. The coordinates of, $P,Q,R$ and $S$ are $\left(a,b,0\right)\left(2a,0,0\right)\left(a,-b,0\right)$ and $\left(0,0,0\right)$ respectively. What is the work done by the field in the process?

Figure shows three points $A,B$ and $C$ in a region of uniform electric Field $\overrightarrow{E}$. The line $AB$ is perpendicular and $BC$ is parallel to the field lines. Then which of the following hold good? ($V_A,V_B$ and $V_C$ represent the electric potential at points $A, B$ and $C$ respectively )

An electron is placed on $X$-axis where the electric potential depends on $x$ as shown in figures (the potential does not depend on $y$ and $z$ ). What is the electric force on the electron?

An imaginary equilateral triangle $ABC$ of side length $2 \mathrm{m}$ is placed in a uniform electric field $\overrightarrow{\mathrm{E}}=10 \mathrm{N} {\mathrm{C}}^{-1}$ as shown. Then. $V_A-V_B=$