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Equation of plane which contains the line x-11=y-23=z-32 and which is perpendicular to the plane 2x+7y+5z=2, is

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Important Questions on Plane

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The vector equation of the plane passing through the intersection of the planes r·i^+j^+k^=1 and r·i^-2j^=-2, and the point 1, 0, 2 is:
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A plane is at a distance of 5 units from the origin and perpendicular to the vector 2i^+j^+2k^. The equation of the plane is
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The vector equation of the plane through the point 2i^j^4k^ and parallel to the plane r·4i^12j^3k^-7=0
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Equation of line of projection of the line 3x-y+2z-1=0=x+2y-z-2 on the plane 3x+2y+z=0 is

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If planes x-cy-bz=0, cx-y+az=0 and bx+ay-z=0 pass through a straight line then a2+b2+c2=
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The equation of the plane containing the line 2x5y+z=3, x+y+4z=5 and parallel to the plane x+3y+6z=1 is
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The distance between the planes x+2y+3z+7=0 and 2x+4y+6z+7=0 is
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Equation of the plane passing through points 1,1,1, 1,-1,1 and -7,-3,-5 is