Expand the following by using the identity ${\left(a-b\right)}^3=a^3-b^3-3ab\left(a-b\right)$

${\left(\frac{a}{11}-1\right)}^3$

Find the product.

$\left(cx+by\right)\left(cx-by\right)\left({\left(cx\right)}^2+{\left(by\right)}^2\right)$

Find the product of $\left(a+1\right)\left(a-1\right)\left(a^2+1\right)$

If $a^2+b^2=40$ and $ab=12$, find $a+b$ and $a-b$.

$64a^3-1$

Simplify:

${\left(2x+3y\right)}^2+{\left(2x-3y\right)}^2$

Simplify:

${\left(1-ab\right)}^2-{\left(1+ab\right)}^2$

Simplify:

${\left(2a-3b+1\right)}^2+{\left(2a-3b-1\right)}^2$

Simplify: