Name: Nomenclature of Coordination Compounds - I
Uploaded: 2019-07-19
Duration: 7 min 4 s
Description: All the chemical compounds are assigned a name, which is done according to a specific rule. How are coordination compounds named? Let’s watch the video to fi...

Question

Explain

{[Co {({NH}_{3})}_{6}]}^{3 +}

is diamagnetic whereas

{[Co {(F)}_{6}]}^{3 -}

is paramagnetic.

Accepted Answer

In this complex, the oxidation number of $Co = + 3$ . According to Hund's rule, the number of unpaired electrons in 3d-subshell of ${}_{27}{Co} [({}_{18}{Ar}) 3 d^{7} 4 s^{2}]$ is three while in ${Co}^{3 +}$ ion $[({}_{18}{Ar}) 3 d^{6}]$ there are four unpaired electrons.

In the complex, ${Co}^{+ 3}$ ion has 6 electrons in $d$ -subshell (one lone pair and 4 bond pairs), as ${NH}_{3}$ is strong field ligand all 6 electrons get paired, thus making the complex diamagnetic.

In this complex, the oxidation number of $Co = + 3$ . According to Hund's rule, the number of unpaired electrons in $3 d$ -subshell of ${}_{27}{Co} [({}_{18}{Ar}) 3 d^{7} 4 s^{2}]$ is three while in ${Co}^{3 +}$ ion $[({}_{18}{Ar}) 3 d^{6}]$ there are four unpaired electrons.

Experiments reveal that the complex has magnetic susceptibility corresponding to 4 unpaired electrons. Due to the presence of unpaired electrons, the compound is paramagnetic.

Therefore, ${[Co {({NH}_{3})}_{6}]}^{3 +}$ is diamagnetic whereas ${[Co {(F)}_{6}]}^{3 -}$ is paramagnetic.

Explain ${[Co {({NH}_{3})}_{6}]}^{3 +}$ is diamagnetic whereas ${[Co {(F)}_{6}]}^{3 -}$ is paramagnetic.

Important Questions on Coordination Compounds

Learn and Prepare for any exam you want !

Explain CoNH363+ is diamagnetic whereas CoF63- is paramagnetic.

Important Questions on Coordination Compounds

Learn and Prepare for any exam you want !

Explain ${[Co {({NH}_{3})}_{6}]}^{3 +}$ is diamagnetic whereas ${[Co {(F)}_{6}]}^{3 -}$ is paramagnetic.