For the water flowing through a horizontal pipe, the pressure at two points are 3 . 5 × 10 5 N m - 2 and 2 . 0 × 10 5 N m - 2 . What is the difference of kinetic energy per unit volume at these points?

Given that P 1 = 3 .5×10 5 Nm - 2 P 2 = 2 .0×10 5 Nm - 2 According to Bernoulli's principle for a horizontal flow, P 1 + 1 2 ρ v 1 2 = P 2 + 1 2 ρ v 2 2 = Constant 3 . 5 × 10 5 + 1 2 ρ v 1 2 = 2 . 0 × 10 5 Nm - 2 + 1 2 ρ v 2 2 ⇒ 1 2 ρ v 2 2 - v 1 2 = ( 3 . 5 - 2 . 0 ) × 10 5 Nm - 2 = 1 . 5 × 10 5 Nm - 2 This is the difference in kinetic energy per unit volume.

E M B I B E

Gamma Question Bank for Medical Physics>Chapter 10 - Mechanical Properties of Fluids>Assignment>Q 60

MEDIUM

NEET

IMPORTANT

Earn 100

Explain why

(i) Mercury does not wet glass

(ii) The hair of a paint brush cling together when taken out of water

(iii) Heavier drops flatten and are not spherical in shape.

Important Questions on Mechanical Properties of Fluids

HARD

NEET

IMPORTANT

Gamma Question Bank for Medical Physics>Chapter 10 - Mechanical Properties of Fluids>Assignment>Q 2

A bent tube is lowered into a water stream as shown in figure. The velocity of the stream relative to the tube is equal to $v = 5 m s^{- 1} .$ The closed upper end of the tube has a small orifice. To what height $h$ will the water jet spurt? $(g = 10 m s^{- 2})$