Bureau's Higher Secondary Elements of Mathematics Vol.1>Chapter 4 - Trigonometric Functions>Exercises- 4(a)>Q 2

EASY

11th Odisha Board

IMPORTANT

Earn 100

Express the following as trigonometric ratios of some acute angles.

$\cos 500 °$

Important Questions on Trigonometric Functions

EASY

11th Odisha Board

IMPORTANT

Bureau's Higher Secondary Elements of Mathematics Vol.1>Chapter 4 - Trigonometric Functions>Exercises- 4(a)>Q 2

Express the following as trigonometric ratios of some acute angles.

$\sec 380 °$

EASY

11th Odisha Board

IMPORTANT

Bureau's Higher Secondary Elements of Mathematics Vol.1>Chapter 4 - Trigonometric Functions>Exercises- 4(a)>Q 3

Find the domains of tangent and cotangent functions.

EASY

11th Odisha Board

IMPORTANT

Bureau's Higher Secondary Elements of Mathematics Vol.1>Chapter 4 - Trigonometric Functions>Exercises- 4(a)>Q 4

Determine the ranges of sine and cosine functions.

EASY

11th Odisha Board

IMPORTANT

Bureau's Higher Secondary Elements of Mathematics Vol.1>Chapter 4 - Trigonometric Functions>Exercises- 4(a)>Q 5

Find a value of

A

when

\cos 2 A = \sin 3 A

.

EASY

11th Odisha Board

IMPORTANT

Bureau's Higher Secondary Elements of Mathematics Vol.1>Chapter 4 - Trigonometric Functions>Exercises- 4(a)>Q 6

Find the value of

\cos 1 ° . \cos 2 ° \dots . . \cos 100 °

.

MEDIUM

11th Odisha Board

IMPORTANT

Bureau's Higher Secondary Elements of Mathematics Vol.1>Chapter 4 - Trigonometric Functions>Exercises- 4(a)>Q 7

Find the value of

\cos 24 ° + \cos 5 ° + \cos 175 ° + \cos 204 ° + \cos 300 °

.

MEDIUM

11th Odisha Board

IMPORTANT

Bureau's Higher Secondary Elements of Mathematics Vol.1>Chapter 4 - Trigonometric Functions>Exercises- 4(a)>Q 8

Evaluate

\tan \frac{π}{20} . \tan \frac{3 π}{20} . \tan \frac{5 π}{20} . \tan \frac{7 π}{20} . \tan \frac{9 π}{20}

.

MEDIUM

11th Odisha Board

IMPORTANT

Bureau's Higher Secondary Elements of Mathematics Vol.1>Chapter 4 - Trigonometric Functions>Exercises- 4(a)>Q 9

Show that

\frac{\sin^{3} (180 ° + A) . \tan (360 ° - A) . \sec^{2} (180 ° - A)}{\cos^{2} (90 ° + A) {cosec}^{2} A . \sin (180 ° - A)} = \tan^{3} A

.