Figure shows charge $\left(\mathrm{q}\right)$ versus voltage $\left(\mathrm{V}\right)$ graph for series and parallel combination of two given capacitors. The capacitances are:

The equivalent capacitance between $A$ and $B$ in the circuit is given below.

Three capacitances, each of 3 $\mu \text{F}$, are provided. These cannot be combined to provide the resultant capacitance of :

Two uncharged capacitors are charged with a battery of $E \mathrm{volt}$. The ratio of charges produced on these capacitors $\left(\frac{Q_1}{Q_2}\right)$ will be

The capacity of a parallel plate condenser is $15 \mu \mathrm{F}$ when the distance between its plates is $6 \mathrm{cm}$. If the distance between the plates is reduced to $2 \mathrm{cm}$, then the capacity of this parallel plate condenser will be 

For the arrangement shown in the figure, identify the correct statement.

Two capacitors $A$ and $B$ with capacities $C_1$ and $C_2$ are charged to a potential difference of $V_1$ and $V_2$, respectively. The plates of the capacitors are connected as shown in the figure. The upper plate of $A$ is positive and that of $B$ is negative. An uncharged capacitor of capacitance $C$ and falls on the free ends to complete the circuit, then