EASY
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Figure shows three regions of magnetic field, each of area A and in each region magnitude of magnetic field decreases at a constant rate α. If E is induced electric field then value of line integral E·dr along the given loop is equal to
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Important Questions on Magnetic Effect of Current and Electromagnetic Induction

MEDIUM
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In an ideal transformer, the voltage and the current in the primary are 200 V and 2 amp respectively. If the voltage in the secondary is 2000 V, then the value of current in the secondary will be:
MEDIUM
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A superconducting loop of radius R has self inductance L. A uniform and constant magnetic field B is applied perpendicular to the plane of the loop. Initially current in this loop is zero. The loop is rotated by 180°. The current in the loop after rotation is equal to
HARD
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In the figure shown, the section EDGF is fixed. A rod having resistance R is moved with constant velocity in a uniform magnetic field B as shown in the figure. DE and FG are smooth and resistanceless. Initially, the capacitor is uncharged. The charge on the capacitor
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EASY
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A vertical rod of length l is moving with constant velocity v towards east. The vertical component of the earth's magnetic field is B and the angle of dip is θ. The induced emf in the rod is:
EASY
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Two identical cycle wheels (geometrically) have different number of spokes connected from centre to rim. One is having 20 spokes and other having only 10 (the rim and the spokes are resistance less). One resistance of value R is connected between the centre and rim. The current in R will be:
EASY
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A constant force F is being applied on a rod of length 'l' kept at rest on two parallel conducting rails connected at ends by resistance R in uniform magnetic field B as shown.
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EASY
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A uniform magnetic field exists in region given by B=3i^+4j^+5k^ T. A rod of length 5 m is placed along y axis is moved along x- axis with constant speed 1 m s-1. Then induced e.m.f. in the rod will be:
MEDIUM
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IMPORTANT
In a L-R growth circuit, inductance and resistance used are 1 H and 20 Ω respectively. If at t=50 ms, current in the circuit is 3.165 A then applied direct current emf is :