Eduwiser's INTEGRAL CALCULUS For JEE Main & Advanced>Chapter 9 - Area Enclosed by Curves>EXERCISE>Q 15

HARD

JEE Main

IMPORTANT

Earn 100

Find the area of the figure lying in the first quadrant and bounded by the curves $y^{2} = 4 x, x^{2} = 4 y$ and $x^{2} + y^{2} = 5 .$

Important Questions on Area Enclosed by Curves

MEDIUM

JEE Main

IMPORTANT

Eduwiser's INTEGRAL CALCULUS For JEE Main & Advanced>Chapter 9 - Area Enclosed by Curves>EXERCISE>Q 16

Find the area included between the curve

y = \sqrt{8 - x^{2}},

the tangent to it at the point with abscissa

x = - 2

and the

x - a x i s

.

EASY

JEE Main

IMPORTANT

Eduwiser's INTEGRAL CALCULUS For JEE Main & Advanced>Chapter 9 - Area Enclosed by Curves>EXERCISE>Q 17

Find the area of the figure bounded by the curve

y = \sin^{- 1} x,

the lines

x = 0

and

y = \frac{π}{2} .

MEDIUM

JEE Main

IMPORTANT

Eduwiser's INTEGRAL CALCULUS For JEE Main & Advanced>Chapter 9 - Area Enclosed by Curves>EXERCISE>Q 18

Determine the area of that portion of circle

x^{2} + y^{2} = 64

which is exterior to the parabola

= \frac{2}{3} + \frac{5}{2} \sin^{- 1} (\frac{2}{\sqrt{5}} \sqrt{1 - \frac{1}{5}} - \frac{1}{\sqrt{5}} \sqrt{1 - \frac{4}{5}})

MEDIUM

JEE Main

IMPORTANT

Eduwiser's INTEGRAL CALCULUS For JEE Main & Advanced>Chapter 9 - Area Enclosed by Curves>EXERCISE>Q 19

Find the area above the

x -

axis included between the parabola

y^{2} = a x

and the circle

= \frac{2}{3} + \frac{5}{2} \sin^{- 1} \frac{3}{5} sq . units

MEDIUM

JEE Main

IMPORTANT

Eduwiser's INTEGRAL CALCULUS For JEE Main & Advanced>Chapter 9 - Area Enclosed by Curves>EXERCISE>Q 20

Find the area bounded by

(x - y) (x + y) = 1

and

x^{2} + y^{2} = 4, x > 0, y > 0 .

MEDIUM

JEE Main

IMPORTANT

Eduwiser's INTEGRAL CALCULUS For JEE Main & Advanced>Chapter 9 - Area Enclosed by Curves>EXERCISE>Q 21

Compute the area of the figure bounded by the straight lines

x = 0, x = 2

and the curves

y = 2^{x}, y = 2 x - x^{2} .

MEDIUM

JEE Main

IMPORTANT

Eduwiser's INTEGRAL CALCULUS For JEE Main & Advanced>Chapter 9 - Area Enclosed by Curves>EXERCISE>Q 22

Compute the area of the figure bounded by the parabolas

x = - 2 y^{2}, x = 1 - 3 y^{2} .

MEDIUM

JEE Main

IMPORTANT

Eduwiser's INTEGRAL CALCULUS For JEE Main & Advanced>Chapter 9 - Area Enclosed by Curves>EXERCISE>Q 23

Compute the area of the region in the first quadrant bounded by the curves

y^{2} = 4 x

and

{(x - 4)}^{2} + y^{2} = 16 .