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Find the area of the region enclosed by y=|x-2|+3, x=2, x-axis and y-axis.

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Important Questions on Coordinate Geometry

EASY
The value of p, for which the points A3,1B5,p and C7,-5 are collinear is
MEDIUM
What is the area (in square units) of the triangular region enclosed by the graphs of the equations x+y=3, 2x+5y=12 and the x-axis?
EASY
The ratio in which the straight line 3x+4y=6 divides the join of the points (2,-1) and (1,1) is
HARD
Quadrilateral formed by the vertices (1,4), (-5,4), (-5,-3) and (1,-3) will be
EASY

The equation of the graph shown here is:

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EASY
The equation of the straight line passing through the point M-5,4, such that the portion of it between the axes is divided by the point M in to two equal halves, is
HARD
Let S be the focus of parabola x2+8y=0 and Q be any point on it. If P divides the line segment SQ in the ratio 1 : 2, then the locus of P is
MEDIUM
Let A=a1,a2 and B=b1, b2 be two points in the plane with integer coordinates. Which one of the following is not a possible value of the distance between A and B?
HARD
If the distance between the points (x,0) and (-7, 0) is 10. Then, the possible values of x are ______.
EASY

In the given figure, AP bisect BAC. If AB=4cm, AC=6 cm and BP=3 cm, then the length of CP is:

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HARD

If A(0,-1), B(2,1) and C(0,3) are the vertices of ABC, then the length of median drawn from A will be

MEDIUM

Find the ratio in which line 3x+2y=17 divides the line segment joined by points 2,5 and 5,2.

EASY
Find the area of ABC Whose vertices are A(10, -6), B(2, 5) and C(-1, 3).
MEDIUM
The centre of a circle is (-6, 4). If one end of the diameter of the circle is at (-12, 8) then the other end is at:
EASY

The solution of linear in equalities x+y5 and x-y3 lies:

HARD
Let ABCD be a square of side length 1 . Let P,Q,R,S be points in the interiors of the sides AD,BC,AB,CD respectively, such that PQ and RS intersect at right angles. If PQ=334, then RS equals
MEDIUM
In a ABC, medians, AD and BE are drawn. If AD=4, DAB=π6 and ABE=π3, then the area of the ABC is
EASY
In ABC, D, E and F are the midpoints of the sides AB, BC and CA, respectively. If AB=12 cm, BC=20 cm and CA=15 cm, then the value of 12DE+EF+DF is:
HARD
Find the area of the triangle formed by the lines x-3y=0, x-y=4 and x+y=4.
MEDIUM

Find the area of the triangle formed with the three straight lines represented by:

i x+y=0ii 3x = 5y; andiii y=3x-12