MEDIUM
10th Chhattisgarh Board
IMPORTANT
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Find the equivalent resistance between A and B in the circuit diagram given below.

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Important Questions on Electric Current and Circuit

MEDIUM
10th Chhattisgarh Board
IMPORTANT
Science (Theory & Practical) Class-10>Chapter 6 - Electric Current and Circuit>Exercise>Q 13
If a potential difference generated by a battery across a circuit of two bulbs, combined in series, is 6 volts, and the potential difference at the first bulb is 2 volts, find out the potential difference at the second bulb?
MEDIUM
10th Chhattisgarh Board
IMPORTANT
Science (Theory & Practical) Class-10>Chapter 6 - Electric Current and Circuit>Exercise>Q 14
If two conducting wires of same length and cross-section are combined first in series and then in a parallel combination, what would be the ratio between the quantity of heat generated in the two series and parallel circuits?
MEDIUM
10th Chhattisgarh Board
IMPORTANT
Science (Theory & Practical) Class-10>Chapter 6 - Electric Current and Circuit>Exercise>Q 15
A  9 volt battery is arranged in series combination with resistors of 2 Ω, 3 Ω, 4 Ω, 5 Ω, 12 Ω, what would be the current flowing through 2 Ω ?
HARD
10th Chhattisgarh Board
IMPORTANT
Science (Theory & Practical) Class-10>Chapter 6 - Electric Current and Circuit>Exercise>Q 16
List the various appliances working on the thermal effect produced by the electric current, which are used in our homes, and discuss their working.
HARD
10th Chhattisgarh Board
IMPORTANT
Science (Theory & Practical) Class-10>Chapter 6 - Electric Current and Circuit>Exercise>Q 17
On a bulb, 200 V-100 W is printed. What would be the resistance of the bulb? If 5 of these bulbs burn for 4 hours, what would be the amount of electricity consumed and cost of electricity, if the rate is 50 paise per unit?
MEDIUM
10th Chhattisgarh Board
IMPORTANT
Science (Theory & Practical) Class-10>Chapter 6 - Electric Current and Circuit>Exercise>Q 18
How would you combine 3 resistances of  2 Ω, 3 Ω and 5 Ω, so that equivalent resistance is 2.5 Ω. Draw the circuit.