Find the measure of all the angles of a parallelogram, if one angle of the adjacent angles is ${20}^{°}$ less than thrice the smallest angle.

In the adjoining figure, $\mathrm{ABCD}$ is a parallelogram. Then $\mathrm{\angle }\mathrm{ABD}$ is

Construct a parallelogram with two adjacent sides measuring $4$ cm and $5.1$ cm and an angle measuring $72°$ in between them.

In a parallelogram $ABCD$, $\angle A=115°$. The measure of $\angle D$ is equal to