Mathematics Crash Course MHT-CET>Chapter 29 - Binomial Distribution>Exercise 1>Q 52

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IMPORTANT

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Find the parameter $P$ of $X$ , if $X$ is a binomial variate with the range ${0, 1, 2, 3, 4, 5, 6}$ and $P (X = 2), P (X = 4)$ .

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Important Questions on Binomial Distribution

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IMPORTANT

Mathematics Crash Course MHT-CET>Chapter 29 - Binomial Distribution>Exercise 1>Q 53

In a binomial distribution

B (n, p = \frac{1}{4}) .

If the probability of at least one success is greater than or equal to

\frac{9}{10},

then

n

is greater than

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Mathematics Crash Course MHT-CET>Chapter 29 - Binomial Distribution>Exercise 1>Q 54

The mean and the variance of a binomial distribution are

4 & 2

respectively. Then the probability of

2

successes is:

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Mathematics Crash Course MHT-CET>Chapter 29 - Binomial Distribution>Exercise 1>Q 55

If

X

follows a binomial distribution with parameters

n = 6

and

p

. If

9 P (X = 4) = P (X = 2)

, then

p =

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Mathematics Crash Course MHT-CET>Chapter 29 - Binomial Distribution>Exercise 1>Q 56

The mean and variance of a binomial variate

X

are

4

and

3

respectively. Then

P (X \geq 1) =

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Mathematics Crash Course MHT-CET>Chapter 29 - Binomial Distribution>Exercise 1>Q 57

If

X ~ B (8, \frac{1}{2}),

then

P (| x - 4 | \leq 2) =

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Mathematics Crash Course MHT-CET>Chapter 29 - Binomial Distribution>Exercise 1>Q 58

If four dice are thrown together, then the probability of getting prime number on exactly two of them, is

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Mathematics Crash Course MHT-CET>Chapter 29 - Binomial Distribution>Exercise 1>Q 59

If in a binomial distribution

n = 4

,

P (X = 0) = \frac{16}{81},

then

P (X = 4)

equals

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IMPORTANT

Mathematics Crash Course MHT-CET>Chapter 29 - Binomial Distribution>Exercise 1>Q 60

If there are

n

independent trials,

p

and

q

the probability of success and failure respectively, then the probability of exactly

r

successes is