Alpha Question Bank for Engineering: Mathematics>Chapter 28 - Application of Derivatives>Exercise-1>Q 46

MEDIUM

JEE Main/Advance

IMPORTANT

Earn 100

Find the points of local maxima/minima of following functions $f (x) = 2 x^{3} - 21 x^{2} + 36 x - 20$ .

Important Questions on Application of Derivatives

EASY

JEE Main/Advance

IMPORTANT

Alpha Question Bank for Engineering: Mathematics>Chapter 28 - Application of Derivatives>Exercise-1>Q 48

Find the points of local maxima/minima of following functions

f (x) = x \ln x

.

MEDIUM

JEE Main/Advance

IMPORTANT

Alpha Question Bank for Engineering: Mathematics>Chapter 28 - Application of Derivatives>Exercise-1>Q 49

Find points of local maxima/minima of

f (x) = (2^{x} - 1) {(2^{x} - 2)}^{2}

.

EASY

JEE Main/Advance

IMPORTANT

Alpha Question Bank for Engineering: Mathematics>Chapter 28 - Application of Derivatives>Exercise-1>Q 50

Find points of local maxima/minima of

f (x) = x^{2} e^{- x}

.

EASY

JEE Main/Advance

IMPORTANT

Alpha Question Bank for Engineering: Mathematics>Chapter 28 - Application of Derivatives>Exercise-1>Q 52

Find points of local maxima/minima of

f (x) = 2 x + 3 x^{2 / 3}

.

HARD

JEE Main/Advance

IMPORTANT

Alpha Question Bank for Engineering: Mathematics>Chapter 28 - Application of Derivatives>Exercise-1>Q 53

Find points of local maxima/minima of $f (x) = |\frac{x^{2} - 2}{x^{2} - 1}|$ .

MEDIUM

JEE Main/Advance

IMPORTANT

Alpha Question Bank for Engineering: Mathematics>Chapter 28 - Application of Derivatives>Exercise-1>Q 54

Draw graph of

f (x) = x | x - 2 |

, and hence find the points of local maxima/minima.

EASY

JEE Main/Advance

IMPORTANT

Alpha Question Bank for Engineering: Mathematics>Chapter 28 - Application of Derivatives>Exercise-1>Q 55

Find the absolute maximum/minimum value of function

f (x) = x^{3}; x \in [- 2, 2]

.

EASY

JEE Main/Advance

IMPORTANT

Alpha Question Bank for Engineering: Mathematics>Chapter 28 - Application of Derivatives>Exercise-1>Q 57

Find the absolute maximum/minimum value of function

f (x) = 4 x - \frac{x^{2}}{2}; x \in [- 2, \frac{9}{2}]

.