Name: Sign Convention
Uploaded: 2019-07-19
Duration: 7 min 37 s
Description: All distances are measured from the optical centre of the lens. Distances measured in the direction opposite to the incident light's direction are considered...

Question

Find the position, size and nature of the image formed by a spherical mirror from the given data: Focal length,

f = - 12 cm

, object distance,

u = - 36 cm

and size of the object, $O = 2 c m$ .

Accepted Answer

Given,
Object distance, $u = - 36 c m$
Size of the object, $O = 2 c m$
Focal length of the spherical mirror, $f = - 12 c m$
Using the mirror formula,
$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$
$\frac{1}{v} = \frac{1}{- 12} - \frac{1}{- 36} \frac{1}{v} = \frac{- 2}{36}$
$v = - 18 c m$
The image is real and it is formed $18 c m$ in front of the mirror.
Magnification( $m$ ) = $\frac{I}{O} = \frac{- v}{u}$

= $\frac{I}{2} = - \frac{- 18}{- 36}$
Hence, $I = - 1 c m$
Size of the image is $O = 2 c m$ and it is inverted.

Find the position, size and nature of the image formed by a spherical mirror from the given data: Focal length, $f = - 12 cm$ , object distance, $u = - 36 cm$ and size of the object, $O = 2 c m$ .

Important Questions on Light

Learn and Prepare for any exam you want !

Find the position, size and nature of the image formed by a spherical mirror from the given data: Focal length, f=-12 cm, object distance, u=-36 cm and size of the object, O=2 cm.

Important Questions on Light

Learn and Prepare for any exam you want !

Find the position, size and nature of the image formed by a spherical mirror from the given data: Focal length, $f = - 12 cm$ , object distance, $u = - 36 cm$ and size of the object, $O = 2 c m$ .