Find the reading of the ideal ammeter connected in the given circuit. Assume that the cells have negligible internal resistance.

The figure shows a balanced Wheatstone bridge.

Two voltmeters and two resistances are connected as shown in the figure. On closing the switch $S$, what will be the effect on the readings of the voltmeters?

Two ideal batteries and two ammeters are arranged as shown in the figure.

In the above figure, if the polarity of $E_2$ is reversed, then

In the figure, the voltmeter is not ideal. If the voltmeter is removed from $R_1$, and then put across $R_2$, what will be the effect on current $I$? Given $R_1>R_2$

Three ammeters $A, B$ and $C$ of resistances $R_A, R_B$ and $R_C,$ respectively, are joined as shown in the figure.

When some potential difference is applied across the terminals $T_1$ and $T_2,$ their readings are $I_A, I_B$ and $I_C,$ respectively, then