Name: Proving Pythagoras Theorem
Uploaded: 2019-07-19
Duration: 3 min 43 s
Description: In this video, we will learn the Pythagoras theorem and the method of proving the Pythagoras theorem by using geometry and algebraic identities in detail.

Question

Find the value of

\sqrt{64432729} - \sqrt{9653449}

.

Accepted Answer

Follow the given steps in long division method:

1. Make a pair of two from right side and put a bar over every pair of digits starting from the right of the given number. If there are odd number of digits, the extreme left digit will be without a bar sign above it.

2. Think of the largest number whose square is equal to or just less than the first period. Take this number as the divisor and also as the quotient.

3. To find the new divisor, double the value of the quotient and write it leaving a blank space next to it. Select the largest digit for the unit place of the divisor such that the new number, when multiplied by the new digit at unit’s place, is equal to or less than the dividend.

4. Repeat the steps till we get remainder as zero.

First, find the square root of $64432729$ by long division method.

$\begin{matrix} 8 & 0 2 7 \\ 8 & 64 & 43 27 29 \\ 64 & ↓ ↓ \\ 1602 & 0 & 4327 \\ 3204 ↓ \\ 16047 & 1168 29 \end{matrix} 1168 29 0$

Therefore, $\sqrt{64432729} = 8027$ .

Next, to find the $\sqrt{9653449}$ by long division method.

$\begin{matrix} 3 & 1 0 7 \\ 3 & 9 & 65 34 49 \\ 9 & ↓ ↓ \\ 61 & 0 & 65 \\ 61 ↓ \\ 620 & 4 34 ↓ \end{matrix} 0 00 6207 4 34 49 4 34 49 0$

Therefore, $\sqrt{9653449} = 3107$ .

Thus, the value of $\sqrt{64432729} - \sqrt{9653449} = 8027 - 3107 = 4920$ .

Find the value of $\sqrt{64432729} - \sqrt{9653449}$ .

Important Questions on Squares and Square Roots

Learn and Prepare for any exam you want !

Find the value of 64432729-9653449 .

Important Questions on Squares and Square Roots

Learn and Prepare for any exam you want !

Find the value of $\sqrt{64432729} - \sqrt{9653449}$ .