Find the value using distributive property. 3524 × 69 + 3524 × 31

The distributive property states that an expression which is given in form of A ( B + C ) can be solved as A × ( B + C ) = A B + A C . 3524 × 69 + 3524 × 31 = 3524 × 60 + 9 + 3524 × 30 + 1 = 3524 × 60 + 3524 × 9 + 3524 × 30 + 3524 × 1 = 211440 + 31716 + 105720 + 3524 = 352400 Hence, required answer is 352400 .

Find the value using distributive property. 3524 × 69 + 3524 × 31

The distributive property states that an expression which is given in form of A ( B + C ) can be solved as A × ( B + C ) = A B + A C . 3524 × 69 + 3524 × 31 = 3524 × 60 + 9 + 3524 × 30 + 1 = 3524 × 60 + 3524 × 9 + 3524 × 30 + 3524 × 1 = 211440 + 31716 + 105720 + 3524 = 352400 Hence, required answer is 352400 .

Find the product using suitable property. 16 × 98

The distributive property states that an expression which is given in form of A ( B + C ) can be solved as A × ( B + C ) = A B + A C . We write 98 a s 90 + 8 = 16 × 90 + 8 = 16 × 90 + 16 × 8 = 1440 + 128 = 1568 Hence, required answer is 1568 .

What should be added to 40 × 30 so that the sum is 12500 ÷ 10 ?

Given, 40 × 30 + x = 12500 ÷ 10 , where x is the number to be added. Calculating RHS, we have: 12500 10 = 1250 On LHS, we have: 40 × 30 + x = 1200 + x Equating LHS and RHS, we get: 1200 + x = 1250 x = 1250 - 1200 = 50 . Hence, the number to be added is 50 .

Find the value of 4815 × 44 + 4815 × 52 + 4 × 4815 using suitable property.

Given, 4815 × 44 + 4815 × 52 + 4 × 4815 To find the value using suitable property. We know, The distributive property of multiplication over addition states that, If a , b and c are three whole numbers, then: a b + a c = a b + c Therefore, we get: 4815 × 44 + 4815 × 52 + 4 × 4815 = 4815 44 + 52 + 4 = 4815 × 100 = 481500 Hence, the required value is 481500 by using distributive property.