Find $x$, if ${\left(\frac{1}{4}\right)}^{-4}\times {\left(\frac{1}{4}\right)}^{-8}={\left(\frac{1}{4}\right)}^{-4x}$

 

Find $x$, if ${\left(\frac{-1}{2}\right)}^{-19}÷{\left(\frac{-1}{2}\right)}^8={\left(\frac{-1}{2}\right)}^{-2x+1}$

Find $x$, if ${\left(\frac{3}{2}\right)}^{-3}\times {\left(\frac{3}{2}\right)}^5={\left(\frac{3}{2}\right)}^{2x+1}$

Find $x$, if ${\left(\frac{2}{5}\right)}^{-3}\times {\left(\frac{2}{5}\right)}^{15}={\left(\frac{2}{5}\right)}^{2+3x}$.

Find $x$, if ${\left(\frac{5}{4}\right)}^{-x}÷{\left(\frac{5}{4}\right)}^{-4}={\left(\frac{5}{4}\right)}^5$

Find $x$, if ${\left(\frac{8}{3}\right)}^{2x+1}\times {\left(\frac{8}{3}\right)}^5={\left(\frac{8}{3}\right)}^{x+2}$

Find the value of $x$ for which $5^{2x}+5^{-3}=5^5$.

Note - The question is copied wrongly from the book and there is a mistake in sign. The correct question is - 

Find the value of $\mathrm{x}$ for which $5^{2x}÷5^{-3}=5^5$.