Five cells each of emf $E$ and internal resistance $r$ are connected in series. If one cell is wrongly connected, then the equivalent emf of the combination is

In figure, the emf of the cell is $2 \mathrm{V}$ and internal resistance is negligible. The resistance of the voltmeter is $80 \mathrm{\Omega }$. The reading of the voltmeter will be

Calculate the current shown by the ammeter $A$ in the circuit shown below

$A$and $B$  are connected to positive and negative terminals of a cell of emf $12 \mathrm{V}$ respectively. The value of voltage shown by voltmeter of negligible resistance is

Five identical lamps each of resistance $R=1100 \mathrm{\Omega }$ are connected to $220 \mathrm{V}$ as shown in figure. The reading of ideal ammeter $A$ is

In the circuit shown, $R_1$ is increased. What happens to the reading of the voltmeter (ideal)?

A voltmeter is connected in parallel with a variable resistance $R$ which is in series with an ammeter and a cell as shown in the figure. For one value of $R,$ the ammeter and voltmeter read as $0.3 \mathrm{A}$ and $0.9 \mathrm{V}$ respectively. For another value of $R$ the readings are $0.25 \mathrm{A}$ and $1.0 \mathrm{V}\text{ respectively}$ What is the internal resistance of the cell?

A combination of five resistors are connected with a cell of emf $10 V$ as shown in figure. The potential difference $V_B-V_E$ will be