For a gaseous reaction, $A+B\to$ products, the energy of activation was found to be $2.27{\mathrm{kJmol}}^{-1}$ at $273\mathrm{K}$. The ratio of the rate constant (k) to the frequency factor (A) at $273\mathrm{K}$ is

The kinetic data recorded at $278\mathrm{K}$ for the reaction

${\mathrm{NH}}_4^{+}\left(\mathrm{aq}\right)+{\mathrm{NO}}_2^{-}\left(\mathrm{aq}\right)\to {\mathrm{N}}_2\left(\mathrm{g}\right)+2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$ is

The kinetic rate expression and the unit of rate constant (k) of the above reaction are respectively

For an elementary rearrangement reaction $\mathrm{A}\rightleftharpoons \mathrm{P}$, the following data were recorded at $303\mathrm{K}$ when $[\mathrm{P}{]}_0=0$

If the equilibrium constant of the reaction is 1.12 at $303\mathrm{K}$, the rate constant for the reaction $\mathrm{P}\to \mathrm{A}$ is:

For the reaction ${\mathrm{N}}_2+3{\mathrm{H}}_2\to$ the rate expression is $-\mathrm{d}\left[{\mathrm{NH}}_3\right]/\mathrm{dt}=\mathrm{k}\left[{\mathrm{H}}_2\right]\left[{\mathrm{N}}_2\right]$

The correct statement is.

$\mathrm{I}$. The reaction is not elementary.

$\mathrm{II}$.  The reaction is of second order.

$\mathrm{III}$. $-\mathrm{d}\left[{\mathrm{H}}_2\right]/\mathrm{dt}=-\mathrm{d}\left[{\mathrm{NH}}_3\right]/\mathrm{dt}$.

Which of the energy values marked as $\mathrm{I}, \mathrm{II}$ and $\mathrm{III}$ in the following diagram, will change by the addition of a suitable catalyst?

Urea, $\mathrm{CO}{\left({\mathrm{NH}}_2\right)}_2,$ decomposes at $90°\mathrm{C}$ as ${\left[\mathrm{CO}\left({\mathrm{NH}}_2\right)\right]}_2\left(\mathrm{aq}\right)\to {\mathrm{NH}}_4^{+}\left(\mathrm{aq}\right)+{\mathrm{OCN}}^{-}\left(\mathrm{aq}\right).$ Experimental data obtained for the reaction is given in the following plot;

From the graph it can be inferred that-

A simple mechanism for enzyme-catalyzed reaction is given by the following set of equations:

$\underset{\left(\mathrm{enzyme}\right)}{\mathrm{E}}+\underset{\left(\mathrm{reactant}\right)}{\mathrm{S}}\rightleftharpoons \underset{(\mathrm{intermediate}-1)}{\mathrm{ES}}$

$\underset{(\mathrm{intermediate}-1)}{\mathrm{ES}}\rightleftharpoons \underset{(\mathrm{intermediate}-2)}{\mathrm{EP}}$

$\underset{(\mathrm{intermediate}-2)}{\mathrm{EP}}\rightleftharpoons \underset{\left(\mathrm{enzyme}\right)}{\mathrm{E}}+\underset{\left(\mathrm{product}\right)}{\mathrm{P}}$

This is known as the Michaelis-Menten mechanism. The potential energy diagram is shown in the figure. Which of the following sets of identifications is correct? (Assume that the temperature and pressure are constant).