HARD
JEE Main/Advance
IMPORTANT
Earn 100

For a gaseous reaction Aproducts, the half-life of the first order decomposition at 400 K is 150 minutes and the energy of activation is 65.0 kJ mole-1. What fraction of molecules of A at 400 K have sufficient energy to give the products?

Important Questions on Chemical Kinetics

HARD
JEE Main/Advance
IMPORTANT

At some temperature, the rate constant for the decomposition of HI on a gold surface is 0.1 Ms-1.

2HIH2g+I2g

What is the order of the reaction? How long will it take for the concentration of HI to drop from 2 M to 0.5 M.

MEDIUM
JEE Main/Advance
IMPORTANT
A certain reaction A+BC, the first order with respect to each reactant k=10-3. Determine the final concentration of A after 100 s, if the initial concentration of A was 0.1 M and that of B was 0.2 M.
EASY
JEE Main/Advance
IMPORTANT

For the complex, Ag++2NH3AgNH32+

dxdt=2×107L2mol-2s-1Ag+NH32-1×10-2s-1 AgNH32+

Hence, ratio of rate constants of the forward and backward reaction is:

MEDIUM
JEE Main/Advance
IMPORTANT

Consider the elementary reaction sequence shown in figure. Which of the following equation correct?

Question Image

HARD
JEE Main/Advance
IMPORTANT

AaqBaq+Caq is a first order reaction,

Time t
Moles of reagent n1 n2

Reaction progress is measure with the help of titration of reagent 'R'. If all A, B and C reacted with reagent and have 'n' factors [n factors; eq.wt =mol. wtn] in the ratio of 1:2:3 with the reagent. The k in terms of t, n1 and n2 is:

MEDIUM
JEE Main/Advance
IMPORTANT
For AK1BK2C,is characterised by:
MEDIUM
JEE Main/Advance
IMPORTANT
Decomposition of H2O2 is a first-order reaction. A solution of H2O2 labeled as 20 volumes was left open. Due to this, some H2O2 is decomposed. To determine the new volume strength after 6 hours, 10 mL this solution was diluted to 100 mL. 10 mL of this diluted solution was titrated against 25 mL of 0.025 M KMnO4 solution under acidic conditions. Calculate the rate constant for the decomposition of H2O2 in second-1. Report your answer as K×106ln 2017.5=0.1335
HARD
JEE Main/Advance
IMPORTANT
A reaction takes place in three steps. The rate constant of the three steps are K1 , K2 and K3 respectively. The overall rate constant K=K1K3K2.
The energy of activation for the three steps are 40 , 30 and 20KJ respectively. Therefore: