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For a particle executing simple harmonic motion, the kinetic energy K is given by, K=K0cos2ωt. The maximum value of potential energy is

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Important Questions on Simple Harmonic Motion

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The potential energy of a particle with displacement X is UX. The motion is simple harmonic when (K is a positive constant)
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The kinetic energy and potential energy of a particle executing simple harmonic motion will be equal, when displacement (amplitude =a) is
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The total energy of the body executing SHM is E. Then the kinetic energy when the displacement is half of the amplitude is
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The potential energy of a particle executing SHM is 2.5 J when its displacement is half of amplitude. The total energy of the particle is,
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The angular velocity and the amplitude of a simple pendulum is ω and a, respectively. At a displacement X from the mean position if its kinetic energy is T and potential energy is V, thén the ratio of T to V is
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When the potential energy of a particle executing simple harmonic motion is one-fourth of its maximum value during the oscillation, the displacement of the particle from the equilibrium position in terms of its amplitude A is
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A particle of mass 10 gm is describing SHM along a straight line with the period of 2 sec and amplitude of 10 cm. Its kinetic energy when it is at 5 cm from its equilibrium position is
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When the displacement is half of the amplitude. The ratio of potential energy to the total energy is -