For designing a voltmeter of range $50 \mathrm{V}$ and an ammeter of range $10 \mathrm{mA}$ using a galvanometer which has a coil of resistance $54 \Omega$ showing a full scale deflection for $1 \mathrm{mA}$ as in figure.

(A) for voltmeter $R\approx 50 \mathrm{k}\Omega$

(B) for ammeter $r\approx 0.2 \Omega$

(C) for ammeter $r\approx 6 \Omega$

(D) for voltmeter $R\approx 5 \mathrm{k}\Omega$

(E) for voltmeter $R\approx 500 \Omega$

Choose the correct answer from the options given below:

The deflection in galvanometer falls to $\left(\frac{1}{4}\right)^{\operatorname{th}}$ when it is shunted by $3 \mathrm{\Omega }$. If additional shunt of $2 \mathrm{\Omega }$ is connected to earlier shunt, the deflection in galvanometer falls to

How do you convert a moving coil galvanometer into an ammeter?

Distinguish between ammeter and voltmeter.

A galvanometer has a 50 division scale. Battery has no internal resistance. It is found that there is deflection of 40 divisions when $\mathrm{R.B.}=2400 \mathrm{\Omega }.$Deflection becomes 20 divisions when resistance taken from resistance box is 4900 Ω. Then we can conclude :



Note: This question is awarded as the bonus. Now the question is corrected.