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For emission line of atomic hydrogen from ni=8 to nf=n, the plot of wave number v- against 1n2 will be: (The Rydberg constant, RH is in wave number unit)

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Important Questions on Structure of Atom

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Which one of the following about an electron occupying the 1s orbital in a hydrogen atom is incorrect? (The Bohr radius is represented by a0 ).
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For any given series of spectral lines of atomic hydrogen, let  Δv-=v-max-v-min  be the difference in maximum and minimum wave number in cm-1

The ratio Δv-Lyman/Δv-Balmar is

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The electron in the hydrogen atom undergoes transition from higher orbitals to orbital of radius 211.6 pm. This transition is associated with
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The total number of orbitals associated with the principal quantum number 5 is:
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The energy of an electron in first Bohr's orbit of H atom is 13.6eV. The energy value of electron in the first excited state of Li 2+ is :
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Hydrogen has three isotopes A, B and C. If the number of neutron(s) in A, B and C respectively, are x, y and z, the sum of x, y and z is
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The radius of the second Bohr orbit, in terms of the Bohr radius, a0, in Li2+ is:
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For the Balmer series, in the spectrum of H atom, v-=RH1n12-1n22, the correct statements among I to IV are,
I As wavelength decreases, the lines in the series converge.
II The integer n1 is equal to 2.
III The lines of the longest wavelength correspond to n2=3.
IV The ionization energy of hydrogen can be calculated from the wave number of these lines.