For spontaneous cooling of a hot metal rod (system) in the air,

Consider the following processes:

                                $\mathrm{\Delta H}(\mathrm{kJ}/\mathrm{mol})$

$\frac{1}{2} \mathrm{A}⟶\mathrm{B} +150$

$3\mathrm{B}⟶2\mathrm{C}+\mathrm{D} -125$

$\mathrm{E}+\mathrm{A}⟶2\mathrm{D} +350$

For $\mathrm{B}+\mathrm{D}⟶\mathrm{E}+2\mathrm{C}, \mathrm{\Delta H}$ will be:

The value of $\mathrm{\Delta H}-\mathrm{\Delta E}$ in $\mathrm{J}$ for the following reaction at $27 °\mathrm{C}$ will be-

$2{\mathrm{NH}}_3\left(\mathrm{g}\right)⟶{\mathrm{N}}_2\left(\mathrm{g}\right)+3{\mathrm{H}}_2\left(\mathrm{g}\right)$