MEDIUM
JEE Main
IMPORTANT
Earn 100

For the Balmer series, in the spectrum of H atom, v-=RH1n12-1n22, the correct statements among I to IV are,
I As wavelength decreases, the lines in the series converge.
II The integer n1 is equal to 2.
III The lines of the longest wavelength correspond to n2=3.
IV The ionization energy of hydrogen can be calculated from the wave number of these lines.

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Important Questions on Structure of Atom

MEDIUM
JEE Main
IMPORTANT

If p is the momentum of the fastest electron ejected from a metal surface after the irradiation of light having wavelength λ, then for 1.5 p momentum of the photoelectron, the wavelength of the light should be:

(Assume kinetic energy of ejected photoelectron to be very high in comparison to work function)

EASY
JEE Main
IMPORTANT
The quantum number of four electrons are given below:
I.  n=4, l=2, ml=2, ms=1/2
II.  n=3, l=2, ml=1, ms=+1/2
III. n=4, l=1, ml=0, ms=+1/2
IV. n=3, l=1, ml=1, ms=1/2
The correct order of their increasing energies will be:
MEDIUM
JEE Main
IMPORTANT
If the shortest wavelength in Lyman series of hydrogen atom is A, then the longest wavelength in Paschen series of He+ is
MEDIUM
JEE Main
IMPORTANT
The number of orbitals associated with quantum numbers n=5,ms=+12 is:
HARD
JEE Main
IMPORTANT
Energy of an electron is given by  E=-2.178×10-18Z2n2 J. Wavelength of light required to excite an electron in a hydrogen atom from level n=1 to n=2 will be :
h=6.62×10-34 Js and c=3.0×108 ms-1
MEDIUM
JEE Main
IMPORTANT
The correct set of four quantum numbers for the valence electrons of rubidium atom Z=37 is
MEDIUM
JEE Main
IMPORTANT
The correct statement about probability density (except at infinite distance from nucleus) is :
MEDIUM
JEE Main
IMPORTANT

The difference between the radii of 3rd and 4th  orbits of Li2+ is ΔR1. The difference between the radii of 3rd and 4th  orbits of He+ is ΔR2. Ratio of  ΔR1:ΔR2 is :