MEDIUM
JEE Main
IMPORTANT
Earn 100

For the Balmer series, in the spectrum of atom, the correct statements among to are,
As wavelength decreases, the lines in the series converge.
The integer is equal to .
The lines of the longest wavelength correspond to .
The ionization energy of hydrogen can be calculated from the wave number of these lines.
(a)
(b)
(c)
(d)

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Important Questions on Structure of Atom
MEDIUM
JEE Main
IMPORTANT
If is the momentum of the fastest electron ejected from a metal surface after the irradiation of light having wavelength then for momentum of the photoelectron, the wavelength of the light should be:
(Assume kinetic energy of ejected photoelectron to be very high in comparison to work function)

EASY
JEE Main
IMPORTANT
The quantum number of four electrons are given below:
The correct order of their increasing energies will be:

MEDIUM
JEE Main
IMPORTANT
If the shortest wavelength in Lyman series of hydrogen atom is , then the longest wavelength in Paschen series of is

MEDIUM
JEE Main
IMPORTANT
The number of orbitals associated with quantum numbers is:

HARD
JEE Main
IMPORTANT
Energy of an electron is given by . Wavelength of light required to excite an electron in a hydrogen atom from level n=1 to n=2 will be :

MEDIUM
JEE Main
IMPORTANT
The correct set of four quantum numbers for the valence electrons of rubidium atom is

MEDIUM
JEE Main
IMPORTANT
The correct statement about probability density (except at infinite distance from nucleus) is :

MEDIUM
JEE Main
IMPORTANT
The difference between the radii of and orbits of is . The difference between the radii of and orbits of is Ratio of is :
