EASY
JEE Main/Advance
IMPORTANT
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For the circuit shown here, the potential difference between points A and B is

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Important Questions on Capacitance

MEDIUM
JEE Main/Advance
IMPORTANT
The plates S and T of an uncharged parallel plate capacitor are connected across a battery. The battery is then disconnected and the charged plates are now connected in a system as shown in the figure. The system shown in equilibrium. All the strings and spring are insulating and massless. The magnitude of charge on one of the capacitor plates is : [Area of plates =A]

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MEDIUM
JEE Main/Advance
IMPORTANT

In the circuit shown in figure C1=2C2. Switch S is closed at time t=0. Let i1 and i2 be the currents flowing through C1 and C2 at any time t, the ratio i1/i2.

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HARD
JEE Main/Advance
IMPORTANT
A parallel plate capacitor is connected to a cell. Its positive plate A and its negative plate B have charges +Q and -Q respectively. A third plate C, identical to A and B, with charge +Q, is now introduced midway between A and B, parallel to them. Which of the following are correct :
HARD
JEE Main/Advance
IMPORTANT
A parallel plate capacitor has a dielectric slab in it. The slab just fills the space inside the capacitor. The capacitor is charged by a battery and then battery is disconnected. Now the slab is started to pull out slowly at t=0. If at time t, capacitance of the capacitor is C, potential difference across is V and energy stored in it is U, then which of the following graphs are correct?
HARD
JEE Main/Advance
IMPORTANT
A capacitor of capacitance C is charged to a potential difference V from a cell and then disconnected from it. A charge + Q is now given to its positive plate. The potential difference across the capacitor is now
EASY
JEE Main/Advance
IMPORTANT
In the adjoining figure, capacitor 1 and 2 have a capacitance 'C' each. When the dielectric of dielectric constant K is inserted between the plates of one of the capacitor, the total charge flowing through battery is-

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EASY
JEE Main/Advance
IMPORTANT
A capacitor C is charged to a potentials difference V and battery is disconnected. Now if the capacitor plates are brought close slowly by some distance
HARD
JEE Main/Advance
IMPORTANT
A parallel plate capacitor of plate area A and plate separation d is charged to potential difference V and then the battery is disconnected. A slab of dielectric constant K is then inserted between the plates of the capacitor so as to fill the space between the plates. If Q,E and W denote respectively, the magnitude of charge on each plate, the electric field between the plates (after the slab is inserted) and the work done on the system, in question, in the process of inserting the slab, then