For the given following invertible matrix, find its inverse by using the definition, $A^{-1}=\frac{1}{\left|A\right|}\left(\mathrm{Adj}\left(A\right)\right)$.

$A=\left(\begin{array}{ll}e& \pi \\ \pi & e\end{array}\right)$

For the given following invertible matrix, find its inverse by using the definition, $A^{-1}=\frac{1}{\left|A\right|}\left(\mathrm{Adj}\left(A\right)\right)$.

$A=\left(\begin{array}{ccc}1& 2& 1\\ -1& 1& 2\\ 1& 0& 1\end{array}\right)$

$3x_1-2x_2+3x_3=8$
$2x_1+x_2-x_3=1$
$4x_1-3x_2+2x_3=4$

$x+y+z=6$
$y+3z=11$
$x-2y+z=0$

$x+2y+z=7$
$2x+y-z=9$
$x+5y+4z=-3$

$x+z=2$
$3x+4y+5z=0$
$2x+3y+4z=-5$

$x+z=0$
$3x+4y+5z=2$
$2x+3y+4z=1$

$x_1+x_2+2x_3=1$
$2x_1+4x_2+4x_3=4$
$3x_1+3x_2+7x_3=-2$