Four plates of equal area$A$ are separated by equal distances $d$ and are arranged as shown in the figure. The equivalent capacity is

Five capacitors of $10 \mu \mathrm{F}$ capacity each are connected to a $DC$ potential of $100 \mathrm{V}$ as shown in the below figure. The equivalent capacitance between the points $A$ and $B$ will be equal to

In the circuit diagram shown in the below figure, the resultant capacitance between points $P$ and $Q$ is

Four capacitors each of capacity $3 \mu \mathrm{F}$ are connected as shown in the below figure. The ratio of equivalent capacitance between $A$ and $B$ and between $A$ and $C$ will be

Three equal capacitors, each with capacitance $C$ are connected as shown in figure. Then the equivalent capacitance between point $A$ and $B$ is

Four plates of the same area of cross-section are joined as shown in the figure. The distance between each plate is $d$. The equivalent capacity across $A$ and $B$ will be:

In the connections shown in the below figure, the equivalent capacity between points $A$ and $B$ will be

The resultant capacitance between $A$ and $B$ in the following figure is equal to