Fraunhofer diffraction from a single-slit of width 1 . 24 × 10 - 6 m is observed with light of wavelength 6200 Å . Calculate the angular width of the central maximum.

Given, Wavelength of light, λ = 6200 Å = 6200 × 10 - 10 m Width of the slit, d = 1 . 24 × 10 - 6 m We can use the relationship d sin θ = λ to find the angular position of the first minima. Where θ is the angular position of the first minima. sin θ = λ d = 6200 × 10 - 10 1 . 24 × 10 - 6 = 1 2 ⇒ θ = 30 ° So, angular width of the central maxima = 2 θ = 60 °

Fraunhofer diffraction from a single-slit of width 1 . 24 × 10 - 6 m is observed with light of wavelength 6200 Å . Calculate the angular width of the central maximum.

Given, Wavelength of light, λ = 6200 Å = 6200 × 10 - 10 m Width of the slit, d = 1 . 24 × 10 - 6 m We can use the relationship d sin θ = λ to find the angular position of the first minima. Where θ is the angular position of the first minima. sin θ = λ d = 6200 × 10 - 10 1 . 24 × 10 - 6 = 1 2 ⇒ θ = 30 ° So, angular width of the central maxima = 2 θ = 60 °

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Fraunhofer diffraction from a single-slit of width $1.24 \times 10^{- 6} m$ is observed with light of wavelength $6200 Å$ . Calculate the angular width of the central maximum.

Important Questions on Diffraction of Light

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ISC Physics Class 12, Part-2>Chapter 8 - Diffraction of Light>QUESTIONS>Q 3

A parallel beam of light of wavelength

600 nm

falls normally on a narrow slit of width

0.3 mm

. Calculate the angular separation between the first minimum and the central maximum.

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ISC Physics Class 12, Part-2>Chapter 8 - Diffraction of Light>QUESTIONS>Q 3

A parallel beam of light of wavelength

600 nm

falls normally on a narrow slit of width

0.3 mm

. Calculate the angular separation between the first subsidiary maxima on the two sides of the central maximum.

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ISC Physics Class 12, Part-2>Chapter 8 - Diffraction of Light>QUESTIONS>Q 4

A parallel beam of light of wavelength

6 \times 10^{- 5} cm

falls normally on a straight slit of width

0.2 mm

. Find the total angular width of the central diffraction maximum and also its linear width as observed on a screen placed

2

metre away.

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ISC Physics Class 12, Part-2>Chapter 8 - Diffraction of Light>QUESTIONS>Q 5

A Fraunhofer diffraction pattern due to a single-slit of width

0.2 mm

is being obtained on a screen placed at a distance of

2

metre from the slit. The first minima lie at

5 mm

on either side of the central maximum on the screen. Find the wavelength of light.

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ISC Physics Class 12, Part-2>Chapter 8 - Diffraction of Light>QUESTIONS>Q 6

A narrow slit of width

0.3 mm

is illuminated normally by a parallel beam of light of wavelength

6 \times 10^{- 7} m

. The Fraunhofer diffraction pattern is obtained on a screen placed in the focal plane of a convex lens of focal length

25 cm

. The lens is placed quite close to the slit. Find the width of central maximum on the screen.

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ISC Physics Class 12, Part-2>Chapter 8 - Diffraction of Light>QUESTIONS>Q 7

A parallel light beam of wavelength

6000 Å

passes through a slit

0.2 mm

wide and forms a diffraction pattern on a screen

1.0 m

away from the slit. Find the width of the central maximum on the screen. What would be the width of this maximum, if the apparatus be immersed in water of refractive index

\frac{4}{3}

EASY

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ISC Physics Class 12, Part-2>Chapter 8 - Diffraction of Light>For DIFFERENT COMPETITIVE EXAMINATIONS>Q 1

At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygens' wavelet from the edge of the slit and the wavelet from the mid-point of the slit is:

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ISC Physics Class 12, Part-2>Chapter 8 - Diffraction of Light>For DIFFERENT COMPETITIVE EXAMINATIONS>Q 2

A parallel monochromatic beam of light is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the first minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of the slit is:

Fraunhofer diffraction from a single-slit of width 1.24×10-6 m is observed with light of wavelength 6200 Å. Calculate the angular width of the central maximum.

Important Questions on Diffraction of Light

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Fraunhofer diffraction from a single-slit of width $1.24 \times 10^{- 6} m$ is observed with light of wavelength $6200 Å$ . Calculate the angular width of the central maximum.