Given below are two statements:
Statement I : The limiting molar conductivity of $\mathrm{KCl}$ (strong electrolyte) is higher compared to that of $\mathrm{CH}_{3} \mathrm{COOH}$ (weak electrolyte).
Statement II : Molar conductivity decreases with decrease in concentration of electrolyte.

In the light of the above statements, choose the most appropriate answer from the options given below:

Consider the cell at $25°\mathrm{C}$

$\mathrm{Zn}\left|{\mathrm{Zn}}^{2+}\left(\mathrm{aq}\right),\left(1 \mathrm{M}\right)\Vert {\mathrm{Fe}}^{3+}\left(\mathrm{aq}\right),{\mathrm{Fe}}^{2+}\left(\mathrm{aq}\right)\right|\mathrm{Pt}\left(\mathrm{s}\right)$

The fraction of total iron present as ${\mathrm{Fe}}^{3+}$ ion at the cell potential of $1.500 \mathrm{V}$ is $\mathrm{x}\times {10}^{-2}$. The value of $\mathrm{x}$ is ______. (Nearest integer)

$\mathrm{Given}:\hspace{0.17em}{{\mathrm{E}}^{\circ }}_{{\mathrm{Fe}}^{3+}|{\mathrm{Fe}}^{2+}}=0.77\mathrm{V}, \hspace{0.17em}{{\mathrm{E}}^{\circ }}_{{\mathrm{Zn}}^{2+}|\mathrm{Zn}}=-0.76\mathrm{V}$

The magnitude of the change in oxidising power of the ${\mathrm{MnO}}_4^{-}/{\mathrm{Mn}}^{2+}$ couple is $\mathrm{x}\times {10}^{-4} \mathrm{V}$ if the ${\mathrm{H}}^{+}$ concentration is decreased from $1 \mathrm{M}$ to ${10}^{-4}\mathrm{M}$ at $25°\mathrm{C}.$ (Assume concentration of ${\mathrm{MnO}}_4^{-}$ and ${\mathrm{Mn}}^{2+}$ to be same on change in ${\mathrm{H}}^{+}$ concentration). The value of $\mathrm{x}$ is __________.

(Rounded off to the nearest integer)

[Given: $\frac{2.303\mathrm{RT}}{\mathrm{F}}=0.059$]

Assume a cell with the following reaction ${\mathrm{Cu}}_{\left(\mathrm{s}\right)}+2{\mathrm{Ag}}^{+}\left(1\times {10}^{-3}\mathrm{M}\right)\to {\mathrm{Cu}}^{2+}(0.250\mathrm{M})+2{\mathrm{Ag}}_{\left(\mathrm{s}\right)}$
${\mathrm{E}}_{\mathrm{cell} }^{\circ }=2.97 \mathrm{V}$

${\mathrm{E}}_{\mathrm{cell} }$ for the above reaction is $\underline{ }$  $\mathrm{V}.$

(Nearest integer)

$[$ Given : $\log 2.5=0.3979, \mathrm{T}=298 \mathrm{K}]$

Potassium chlorate is prepared by electrolysis of $\mathrm{KCl}$ in basic solution as shown by following equation.

$6{\mathrm{OH}}^{-}+{\mathrm{Cl}}^{-}\to {\mathrm{ClO}}_3^{-}+3{\mathrm{H}}_2\mathrm{O}+6{\mathrm{e}}^{-}$

A current of $\mathrm{xA}$ has to be passed for $10 \mathrm{h}$ to produce $10.0 \mathrm{g}$ of potassium chlorate. the value of $\mathrm{x}$ is __________. (Nearest integer)

(Molar mass of ${\mathrm{KClO}}_3=122.6 \mathrm{g}{ \mathrm{mol}}^{-1} \mathrm{F}=96500 \mathrm{C}$)

For the disproportionation reaction $2{\mathrm{Cu}}^{+}\left(\mathrm{aq}\right)\rightleftharpoons \mathrm{Cu}\left(\mathrm{s}\right)+{\mathrm{Cu}}^{2+}\left(\mathrm{aq}\right)$ at $298\mathrm{K},$ $\ln \left(\mathrm{K}\right)$  (where $\mathrm{K}$ is the equilibrium constant) is _______$\times {10}^{-1}$

Given $:\left(\mathrm{E}{°}_{{\mathrm{Cu}}^{2+}/{\mathrm{Cu}}^{+}}=0.16V E{°}_{{\mathrm{Cu}}^{+}/\mathrm{Cu}}=0.52\mathrm{V}\frac{\mathrm{RT}}{\mathrm{F}}=0.025\right)$

The Gibbs energy change (in $\mathrm{J}$) for the given reaction at $\left[{\mathrm{Cu}}^{2+}\right]=\left[{\mathrm{Sn}}^{2+}\right]=1\text{\hspace{0.17em}M}$ and $298 \mathrm{K}$ is :

$\mathrm{Cu}\left(\mathrm{s}\right)+{\mathrm{Sn}}^{2+}\left(\mathrm{aq}.\right)\to {\mathrm{Cu}}^{2+}\left(\mathrm{aq}.\right)+\mathrm{Sn}\left(\mathrm{s}\right)$; 

$\left({\mathrm{E}}_{{\mathrm{Sn}}^{2+}\left|\mathrm{Sn}\right.}^0=-0.16\mathrm{V},{\mathrm{E}}_{\left.{\mathrm{Cu}}^{2+}\right|\mathrm{Cu}}^0=0.34\mathrm{V},\right.$Take $\left.\mathrm{F}=96500\mathrm{C}{\mathrm{mol}}^{-1}\right)$